3a^2+12=-12a

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Solution for 3a^2+12=-12a equation: 



3a^2+12=-12a

We move all terms to the left:

3a^2+12-(-12a)=0

We get rid of parentheses

3a^2+12a+12=0

a = 3; b = 12; c = +12;
Δ = b2-4ac
Δ = 122-4·3·12
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{-12}{6}=-2$

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